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what a quid - DNSFLEX

📅 March 12, 2026 👤 scraface

Mar 12, 2026

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📌 Setting the diagonal equal to the diameter of the circle, we have:

📌 s\sqrt{2} = 10

📌 Solving for \(s\), we divide both sides by \(\sqrt{2}\):

📌 s = \frac{10}{\sqrt{2}} = 5\sqrt{2}

📌 The area \(A\) of the square is:

📌 A = s^2 = (5\sqrt{2})^2 = 25 \times 2 = 50

📌 Thus, the area of the square is \(\boxed{50}\).

📌 Question:** A cylinder has a height equal to twice its radius. If the total surface area of the cylinder is \(54\pi\) square units, find the radius of the cylinder.

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