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📅 March 11, 2026 👤 scraface

Mar 11, 2026

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3x - 4y = 12 \quad \text{(1)}\\
2x + 5y = 10 \quad \text{(2)}
Use elimination. Multiply equation (1) by 5 and equation (2) by 4:
15x - 20y &= 60 \quad \text{(from (1))\times 5} \\
8x + 20y &= 40 \quad \text{(from (2))\times 4}
\end{aligned}
Add the equations:
Substitute \( x = \frac{100}{23} \) into equation (2):
2\left(\frac{100}{23}\right) + 5y = 10 \Rightarrow \frac{200}{23} + 5y...
\Rightarrow 5y = 10 - \frac{200}{23} = \frac{230 - 200}{23} = \frac{30...

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