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Home » The area of the circular sector is: - DNSFLEX

The area of the circular sector is: - DNSFLEX

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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x^2 + 3x = \left(x + \frac{3}{2}\right)^2 - \frac{9}{4}
f(x) = 4\left(\left(x + \frac{3}{2}\right)^2 - \frac{9}{4}\right) + 9...
項 \(4\left(x + \frac{3}{2}\right)^2\) は常に非負であり、\(\left(x + \...
\(x = -\frac{3}{2}\) を元の関数に代入します:
f\left(-\frac{3}{2}\right) = 4\left(-\frac{3}{2} + \frac{3}{2}\right)^...
したがって、関数 \(f(x) = 4x^2 + 12x + 9\) の最小値は \(\boxed{0}\) で...
問題: \(\left(\cos x + \sec x\right)^2 + \left(\sin x + \csc x\right)^...
\cos x + \sec x = \cos x + \frac{1}{\cos x}, \quad \sin x + \csc x = \...
\left(\cos x + \frac{1}{\cos x}\right)^2 + \left(\sin x + \frac{1}{\si...
\left(\cos x + \frac{1}{\cos x}\right)^2 =

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