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Home » Let dimensions be \(x\), \(2x\), \(3x\). - DNSFLEX

Let dimensions be \(x\), \(2x\), \(3x\). - DNSFLEX

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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📝 Recent Posts

\sqrt{2 + 2(-1)} = \sqrt{0} = 0
Thus, the minimum value is $ \boxed{0} $.
Question: Find the range of the function $ f(x) = \frac{1}{\sin^2 x +...
Solution: Since $ \sin^2 x + \cos^2 x = 1 $, we write $ f(x) = \frac{1...
Question: Find all angles $ z \in [0^\circ, 360^\circ] $ such that $ \...
Solution: Start with $ \tan z + \cot z = 2 $. Recall $ \tan z = \frac{...
\tan z + \cot z = \frac{\sin z}{\cos z} + \frac{\cos z}{\sin z} = \fra...
Set $ \frac{1}{\sin z \cos z} = 2 $. Then $ \sin z \cos z = \frac{1}{2...
2z = 90^\circ + 360^\circ n \Rightarrow z = 45^\circ + 180^\circ n
Within $ [0^\circ, 360^\circ] $, the solutions are $ z = 45^\circ $ an...

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