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Home » I: Nitrogen oxide emission rate - DNSFLEX

I: Nitrogen oxide emission rate - DNSFLEX

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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📌 A particle moves in a straight line with its position given by \( s(t) = 2t^3 - 5t^2 + 4t \). Find its velocity at \( t = 3 \) seconds.

📌 Velocity is the derivative of position: \( v(t) = rac{ds}{dt} = rac{d}{dt}(2t^3 - 5t^2 + 4t) \).

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\[ p = \frac{\frac{330}{29}}{3} \]
\[ p = \frac{330}{87} = \frac{110}{29} \]
Thus, the costs per liter are:
\[ \boxed{p = \frac{110}{29}, \, q = \frac{49}{29}} \]### Question 1
二次方程式は、方程式 \(x^2 - 5x + 6 = 0\) の根の2倍と3倍を根として持ち...
まず、方程式 \(x^2 - 5x + 6 = 0\) の根を求めます。
\[ x^2 - 5x + 6 = (x - 2)(x - 3) = 0 \]
したがって、根は \(x = 2\) と \(x = 3\) です。
新しい方程式の根はこれらの根の2倍と3倍です：
2倍: \(2 \times 2 = 4\) と \(2 \times 3 = 6\)

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ä¸å¿ã \((h, k)\) ã§åå¾ã \(r\) ã®åã®æ¹ç¨å¼ã¯æ¬¡ã®ã¨...
ä¸ããããä¸å¿ \((3, -2)\) ã¨åå¾ \(5\) ãä»£å¥ãã¾ã:
ç¹ \((6, 1)\) ãåä¸ã«ãããç¢ºèªãã¾ã:
\(18
eq 25\) ãªã®ã§ãç¹ \((6, 1)\) ã¯åä¸ã«ã¯ããã¾ããã
#### \((x - 3)^2 + (y + 2)^2 = 25\), ç¹ \((6, 1)\) ã¯åä¸ã«ãã...
äºæ¬¡æ¹ç¨å¼ \(2x^2 - 4x - 6 = 0\) ãä¸ãããã¦ãã¾ããäº...
x = rac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\(2x^2 - 4x - 6 = 0\) ã§ã¯ã\(a = 2\)ã\(b = -4\)ã\(c = -6\) ã§...
b^2 - 4ac = (-4)^2 - 4 imes 2 imes (-6) = 16 + 48 = 64

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