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Home » freaked! Today’s Easy 7-Letter Phrases Hold the Answers — Try Them Now! - DNSFLEX

freaked! Today’s Easy 7-Letter Phrases Hold the Answers — Try Them Now! - DNSFLEX

📅 March 12, 2026 👤 scraface

Mar 12, 2026

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📌 x \approx 2.62 \quad \text{but exact form: } x = \sqrt[3]{18}

📌 However, note \( 18 = 2 \cdot 3^2 \), so no perfect cube — but problem likely expects exact cube:

📌 Check: \( 2.62^3 \approx 18 \)? Yes.

📌 But since \( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{18} \)

📌 So the width is \( \sqrt[3]{18} \) meters.

📌 But wait — factor:

📌 \( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{18} \)

📌 Alternatively, check if integer solution: try \( x = 3 \):

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Calculate \( 50^2 = 2500 \).
Multiply: \( 2500 \times 0.866 = 2165 \).
Divide by \( 9.8 \): \( R \approx 2165 / 9.8 \approx 220.92 \).
#### 220.92 meters
A car accelerates from rest at a constant rate of \( 3 \, \text{m/s}^2...
Use the formula for distance \( s \) under constant acceleration: \( s...
Initial velocity \( u = 0 \), acceleration \( a = 3 \, \text{m/s}^2 \)...
Substitute the values: \( s = 0 \times 10 + \frac{1}{2} \times 3 \time...
Calculate \( \frac{1}{2} \times 3 \times 100 = 150 \).
#### 150 meters

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