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Home » FF14 Patch Notes You Were Too Busy to Check—This One Changed Everything! - DNSFLEX

FF14 Patch Notes You Were Too Busy to Check—This One Changed Everything! - DNSFLEX

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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setzen wir die Vieta’schen Werte ein:
\sum w_i^2 = 8^2 - 2 \cdot 9 = 64 - 18 = 46.
Wir müssen überprüfen, ob alle Wurzeln \( w_i \) reell und positiv sin...
\( f'(w) = 3w^2 - 16w + 9 \). Diskriminante: \( 256 - 108 = 148 > 0 \)...
\( w = \frac{16 \pm \sqrt{148}}{6} = \frac{16 \pm 2\sqrt{37}}{6} = \fr...
Approximiere \( \sqrt{37} \approx 6.08 \), also:
\( w_1 \approx \frac{8 - 6.08}{3} \approx 0.64 \), \( w_2 \approx \fra...
Berechne \( f(0.64) \approx (0.64)^3 - 8(0.64)^2 + 9(0.64) - 18 \appro...
\( f(4.69) \approx (4.69)^3 - 8(4.69)^2 + 9(4.69) - 18 \approx 102.7 -...
und \( f(6) = 216 - 288 + 54 - 18 = -36 < 0 \), \( f(5) = 125 - 200 +...

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= 60\pi + 36\pi = 96\pi
\text{Surface Area} \approx 96 \times 3.1416 = 301.5936
#### 301.59
A sphere has a volume of 288π cubic centimeters. What is the radius of...
The volume of a sphere is given by:
Setting the volume equal to \( 288\pi \):
\frac{4}{3} \pi r^3 = 288\pi
Dividing both sides by \(\pi\):
\frac{4}{3} r^3 = 288
Solving for \( r^3 \):

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