#### \(\frac415\)1. **Question**: A car travels from City A to City B at an average speed of 60 miles per hour, taking 4 hours. On the return trip, due to heavy traffic, the car travels at an average speed of 40 miles per hour. How much longer does the return trip take compared to the trip from City A to City B? - DNSFLEX

Understanding the Context

The Journey Breakdown

• Outbound Trip (City A to City B): The car travels at a steady speed of 60 miles per hour (mph) and takes 4 hours. Distance = Speed × Time Distance = 60 mph × 4 hours = 240 miles

• Return Trip (City B to City A): On the return, heavy traffic reduces speed to 40 miles per hour. The distance remains the same: 240 miles Time = Distance ÷ Speed Time = 240 miles ÷ 40 mph = 6 hours

Key Insights

Calculating the Time Difference

To find out how much longer the return trip takes: Return time – Outbound time = 6 hours – 4 hours = 2 hours longer

Conclusion

Due to slower traffic on the return journey, the trip takes 2 hours longer than the original 4-hour drive. This example emphasizes the importance of considering real-world conditions like traffic when estimating travel time. By knowing the distances and speeds, you can better prepare for round-trip planning—saving time, fuel, and stress on every journey.

Final Thoughts

Key Facts (for reference):

| Segment | Speed (mph) | Time (hrs) | Distance (miles) | |-------------------|-------------|------------|------------------| | Outbound from A to B | 60 | 4 | 240 | | Return from B to A | 40 | 6 | 240 | | Time Difference | | | +2 hours longer |

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By applying basic division and multiplication formulas, they say every mile’s journey shortens or lengthens depending on conditions—making math an essential tool for smarter travel.