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Home » $ 4 = \frac\ln(2)k $ - DNSFLEX

$ 4 = \frac\ln(2)k $ - DNSFLEX

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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Contradiction again. So the only way this works is if the sequence is...
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C'(t) = rac{(3)(t^2 + 4) - (3t + 2)(2t)}{(t^2 + 4)^2}
3(t^2 + 4) - 2t(3t + 2) = 3t^2 + 12 - (6t^2 + 4t) = -3t^2 - 4t + 12
C'(t) = rac{-3t^2 - 4t + 12}{(t^2 + 4)^2}
To find where $ C(t) $ is increasing, we solve:
-3t^2 - 4t + 12 > 0
This is a quadratic inequality. First, find the roots:

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