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Home » \( 150 = \frac102(2 \cdot 5 + 9d) = 5(10 + 9d) \). - DNSFLEX

\( 150 = \frac102(2 \cdot 5 + 9d) = 5(10 + 9d) \). - DNSFLEX

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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\boxed{10\pi x^2}
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\boxed{x\sqrt{3}}
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📝 Recent Posts

\[ 4x + 6 = -x + 2 \]
\[ 4x + x = 2 - 6 \]
\[ 5x = -4 \]
\[ x = -\frac{4}{5} \]
Substitute \(x = -\frac{4}{5}\) into \(y = 2x + 3\):
\[ y = 2\left(-\frac{4}{5}\right) + 3 = -\frac{8}{5} + \frac{15}{5} =...
Thus, the intersection point is \(\left(-\frac{4}{5}, \frac{7}{5}\righ...
\(\boxed{\left(-\frac{4}{5}, \frac{7}{5}\right)}\)
An entomologist simplifies a complex ratio of wingbeat frequencies giv...
Multiply numerator and denominator by the conjugate of the denominator...

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